反转32 signed int
int reverse(int x) {
long num=0;
while(x!=0){
num=num*10+x%10;
x/=10;
if(num<INT_MIN||num>INT_MAX){
cout<<"??"<<endl;
return 0;
}
}
return (int)num;
}
INT_MIN INT_MAX 定义在<limits.h>中
INT_MAX 0x7fffffff
该解法不具有通用性，如果是int64为，可能出问题。
下午晚上重写
LeetCode解题链接 干货！LeetCode 题解汇总 7. Reverse Integer Reverse ...
Leetcode-7-（整数反转）[https://leetcode-cn.com/problems/revers...
一、题目 LeetCode-7.整数反转链接：https://leetcode-cn.com/problems/r...
LeetCode(7. Reverse Integer) Reverse digits of an integer...
7. Reverse Integer 给定一个32bit的有符号整型，将它倒序输出 Example 1 输入：12...
Problem DescriptionGiven a 32-bit signed integer, reverse...
反转32 signed int INT_MIN INT_MAX 定义在 中INT_MAX 0x7fffffff该解...
问题：Reverse digits of an integer. Example1:x = 123, return...
Algorithm OJ address Leetcode website : 7. Reverse Intege...
title: 'Swift LeetCode 系列之 7: Reverse Integer'date: 2017-...
本文标题：leetcode 7
本文链接：https://www.haomeiwen.com/subject/ivlsuxtx.html
网友评论