Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array.
For example,
Given nums = [0, 1, 3] return 2.
Already Pass Solution
public int MissingNumber(int[] nums) {
int result = nums.Length * (nums.Length + 1) / 2;
foreach(int i in nums)
{
result -= i;
}
return result;
}
解决思路：
(1)利用遗失这个条件，用没有遗失的状态求出遗失的部分
(2)使用foreach比for会快一些
待思考：
(1)如果丢失的数字为几个该如何解决
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本文标题：268. Missing Number
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